Question 69223
Assume you mean:
:
{{{((6a^2-8a-8)) / ((a-2))}}}
------------------
{{{((2a^2-9a-56)) /(( a-8))}}}
:
Remember when you divide fraction, you invert the dividing fraction and multiply
{{{((6a^2-8a-8)) / ((a-2))}}} * {{{((a-8))/((2a^2-9a-56))}}}
:
{{{(2(3a^2-4a-4)) / ((a-2))}}} * {{{((a-8))/((2a^2-9a-56))}}}: factor out 2
:
{{{(2(3a+2)(a-2)) / ((a-2))}}} * {{{((a-8))/((2a+7)(a-8))}}}; factor the quadratics
:
Notice you can cancel out (a-2) and (a-8), you end up with:
:
{{{(2(3a+2)) / ((2a+7)))}}}