<PRE><B>Question 818650</B>
j = (i + 2)
ij = 2(i + j) + 11
---
ij = 2(i + j) + 11
ij = 2(i + j) + 11
ij = 2i + 2j + 11
i(i + 2) = 2i + 2(i + 2) + 11
ii + 2i = 2i + 2i + 4 + 11
ii - 2i - 15 = 0
i^2 - 2i - 15 = 0
---
the above quadratic equation is in standard form, with a=1, b=-2, and c=-15
---
to solve the quadratic equation, by using the quadratic formula, plug this:
1 -2 -15
into this: https://sooeet.com/math/quadratic-equation-solver.php
---
the two real roots (i.e. the two solutions), of the quadratic are:
i = 5
i = -3
---
the problem statement doesn&#39;t prohibit negative integers, so there are two solutions:
---
first solution:
i = 5
j = 7
---
second solution:
i = -3
j = -1
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Convert fractions, decimals, and percents:
https://sooeet.com/math/fraction-decimal-percent.php
---
Calculate and graph the linear regression of any data set:
https://sooeet.com/math/linear-regression.php</PRE>