Question 818650
let x and x+2 be our consecutive odd integers, then
x * (x+2) = (2 * (x + x + 2)) + 11
x^2 +2x = 2x +2x +4 +11
x^2 = 2x +15
x^2 -2x -15 = 0
this quadratic can be factored
(x-5)*(x+3) = 0
x = 5 or -3
we have two possible sets of solutions
5, 7 or
-3, -1
let's check our answers
5 * 7 = 2*(5+7) +11
35 = 24 +11
35 = 35
so first set of answers checks
-3 * -1 = 2 * (-3 -1) +11
3 = -8 +11
3 = 3
our second set of answers checks