Question 818488
<pre>
h(t) = -16t^2 + 50t + 6

Extreme values of a parabola occur at the vertex, so 
the vertex formula:

The t-coordinate is found by the formula {{{-b/(2a)}}}

{{{-b/(2a)}}} = {{{-(50)/(2(-16))}}} = {{{25/16}}} or 1.5625 seconds.

That's the answer you were asked to find.


The h-coordinate is found by substituting the t-value
into the formula

h(t) = -16t^2 + 50t + 6

h{{{(25/16)}}} = -16{{{(25/16)^2}}} + 50{{{(25/16)}}} + 6

the answer is 59.125 feet.  That's the highest point it reaches,
and it reaches that in 1.5625 seconds.

Edwin</pre>