Question 69219
find the LCD of 
    1       1
------- + ------
1 - x^2    x - 1

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Multiply numerator and denominator of the 1st fraction
by negative one to get:

[-1/(x^2-1)] + [1/(x-1)]

Factor to get:

=[-1/(x-1)(x+1)] + [1/(x-1)]

The lcd is (x-1)(x+1)

Rewrite each fraction with the lcd as its denominator:

=[-1/lcd + (x+1)/lcd]

Combine the numerators to get:

=[-1+x+1]/lcd

=x/(x+1)(x-1)

Cheers,
Stan H.

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