<PRE><B>Question 818289</B>
log5(3x+7) + log5(x-5)= 2log5(5)

log5(3x+7) + log5(x-5)= log5(5^2)
log5( (3x+7)/(x-5) ) = log5(25)

{{{(3x+7)/(x-5)  = 25/1}}}

{{{(3x+7)  = 25(x-5)}}}
{{{3x+7  = 25x-125)}}}
Subtract 3x from each side.
{{{7  = 22x-125)}}}
Add 125 to each side.
132 = 22x
  6 = x</PRE>