Question 818399
xlog(45) = 9 + e^1.9
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You have an e, the base of natural logs.
Is the log(45) supposed to be ln(45) ?
Or the common log, {{{log(10,45)}}} ?
I'll assume common log, base 10.
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x = (9 + e^1.9)/log(45)
x =~ (9 + 6.68589442)/log(45)
x =~ 15.68589442/1.653212514
x =~ 9.488129512