Question 818084
1. solve by factoring    
 4w^2-25=0

(2w-5)(2w+5)=0

so either 2w-5=0
or2w+5=0

2w-5=0
2w=5
w=5/2

2w+5=0
2w=-5
w=-5/2

w=+/- 5/2


2. Solve by Quadratic formula
                               3/4(x^2)-2x+3/4=0


a=	0.75	,	b=	-2	,	c=	0.75	
								
b^2-4ac=	4	+	-2.25					
b^2-4ac=	1.75							
{{{	sqrt(	1.75	)=	1.32	}}}			
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	2	+	1.32	)/	1.5			
x1=	2.22							
{{{x2=(-b-sqrt(b^2-4ac))/(2a)}}}								
x2=(	2	-1.32	) /	1.5				
x2=	0.45