Question 817903
In a list of integers, 3 of the integers are even, and the rest are odd
If an integer is selected at random from the list, the probability is 4/5 that the integer will be odd. How many integers are in the list?
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Let "x" be the number of integers.
Then x-3 is the number of odd integers.
Equation:
P(odd) = x-3/x = 4/5
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Solve for "x":
5(x-3) = 4x
5x-15 = 4x
x = 15 (number of integers)
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Cheers,
Stan H.
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