Question 817892
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
 x^2 + 4x + 3  0r (x+2)^2 - 1  V(-2,-1) Opening Upward
(x+3)(x+1) > 0  when  -3 > x >-1
(x+3)(x+1) < 0  when  -3 > x <-1
{{{drawing(300,300,   -6, 6, -6, 6, grid(1), 
circle(0, 3,0.3),
circle(-2, -1,0.3),
graph( 300, 300, -6, 6, -6, 6,0,x^2 + 4x + 3))}}}