Question 68977
3b to the power of 2 divided by 9b to the power of 5


{{{3b^2/9b^5}}}  this equals

{{{(3*b*b)/(9*b*b*b*b*b)}}}  divide numerator and denominator by 3*b*b and we have:


{{{1/3b^3}}}---------------ans


Hope this helps----ptaylor