Question 817167

log(5)k - log(5)k-1 = 1
log(5)(k/(k-1) = 1
Notice that 1 = log(5)
so, log(5)(k/(k-1) = log(5)
and  k/(k-1) = 5
     k/(k-1) = 5/1
finding cross products
     k = 5(k-1)
     k = 5k -5
    -4k = -5
     k = 5/4