Question 817316
log(base7)(7) = 1, think 7^1 = 7

so log(base7)(x) - log(base7)(3x-5) = log(base7)(7)

Since in general log(u/v) = log(u) - log(v)

   log(base7)( x / (3x-5) ) = log(base7)(7)
So   x / (3x-5) = 7/1
     x = 7(3x-5)
     x = 21x -35
   -20x = -35
     x = 35/20
     x = 7/4