Question 817257
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Hi,
{{{A/2 +B/5 =1/3 }}} solve terms of A=
{{{A/2 +B/5 =1/3 }}}    |Multiplying thru by 30 so as all denominators = 1
  15A + 6B = 10
    15A = -6B + 10
      A = {{{(-6B + 10)/15 = -2(3B-5)/15}}}