<PRE><B>Question 816934</B>
how to factor 
4y^2-14y+6
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= 2(2y^2-7y+3)
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= 2(2y^2-6y-y+3)
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= 2(2y(y-3)-(y-3))
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= 2(y-3)(2y-1)
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Cheers,
Stan H.
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