Question 816825
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Hi,
Find the quadratic that has the following characteristics: 
vertex : (-3,2), Y-intercept: (0, -7) 
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex
 y = a(x+3)^2 + 2     Using P(0,-7)
 -7 = 9a + 2
 -9  = 9a
 -1 = a     {{{y = -(x+3)^2 + 2 }}} 
{{{drawing(300,300,   -6, 6, -8, 6, grid(1), 
circle(0, -7,0.3),
circle(-3, 2,0.3),
graph( 300, 300, -6, 6, -8, 6,0,-(x+3)^2 + 2 ))}}}