Question 816799
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
log3(2x-1) = log3
log3(2x-1) - log3 = 0           1st Step
{{{log(3,((2x-1)/3 )) = 0}}}     *[tex \large\ \ log_bx - log_by = log_b(x/y) ]
   {{{(2x-1)/3 = 3^0}}}      
    {{{(2x-1)/3 =1}}}          *[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
          2x-1 = 3
           x = 2