Question 816712

solve. 8^2x-3 =1/16

<pre>
{{{8^(2x - 3) = 1/16}}}
{{{(2^3)^(2x - 3) = 2^- 4}}} ----- Converting to base 2
{{{2^(3(2x - 3)) = 2^- 4}}}
{{{2^(6x - 9) = 2^- 4}}}
6x - 9 = - 4 ----- Bases are equal and so are their exponents
6x = 5
{{{highlight_green(x = 5/6)}}}
You can do the check!! 

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