Question 816727
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
The sum of three consecutive numbers x,  (x+1),  (x+2)
is eight more than twice the lowest number. What are the three numbers?
Question states***
{{{x +  (x+1) +  (x+2) = 2x+8}}}   |Solving for x
  3x + 3 = 2x + 8
      x = 5, the numbers are  5, 6, 7
CHECKING our answer***
{{{5 + 6 + 7 = 2*5 + 8 = 16}}}