Question 816712
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Hi,
The idea is to try to find the same base on both sides of the EQ
{{{8^(2x-3) = 1/16}}}****
{{{8^(2x-3) = 16^(-1)}}}
{{{8^(2x-3) = (8^(4/3))^(-1)}}}
{{{8^(2x-3) = (8^(-4/3))}}}
  2x-3 = -4/3
 6x-9 = -4
  6x = 5
   x = 5/6
CHECKING our answer***
 {{{8^(5/3- 9/3) = 8^(-4/3) = 1/16}}}