Question 816655
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Hi,
Note: Your question involves a Binomial Distribution
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p = .2 & q =.8 and n = 5    nCx = {{{n!/(x!(n-x)!)}}}
The probability that any given rose flower will show measurable damage when temperature rises beyond a specified level is 0.2. 
If the temperature rises to this level, what is the probability that in a sample of 5 flowers:
(c) none is damaged P(x = 0) = (.2^0)(.8^5)= .3277
 (d) all five are damaged P(x=5) = (.2^5)(.8^0) = .0003
 (e) less than two are damaged P(x<2) = P(x=0) + P(x=1) = (.2^0)(.8^5) + 5(.2^1)(.8^4)=  .3277 + .4096 = .7373
 (f) no more that one flower is damaged (same as 'e')
 (g) at least two are damaged = 1 - (P(x=0) + P(x=1)) = 1-.7373 = .2627