Question 816620
-x+y=2
x^2+y^2=20

-x+y=2

y=x+2


x^2+y^2=20

substitute y

x^2+(x+2)^2=20

x^2+x^2+4x+4=20

2x^2+4x-16=0

/2
x^2+2x-8=0

x^2+4x-2x-8=0
x(x+4)-2(x+4)=0

(x+4)(x-2)=0

x=-4 or x=2

y=x+2

when x=-4
y=-4+2=-2
(-4,-2)

when x=2
y=2+2=4
(2,4)