Question 816608
The ages of A and B are in the ratio 4:3. in eight years time the ratio of their ages will be 9:7. find their present ages. if n years ago, A was three times as old as B, find the value of n.
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Now DATA:
A is 4x ; B is 3x
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8 years from now DATA:
A is 4x+8 ; B is 3x+8
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Equations:
4x+8 = 9k
3x+8 = 7k
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Rearrange:
4x - 9k = -8
3x - 7k = -8
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Modify for elimination:
12x - 27k = -24
12x - 28k = -32
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Subtract and solve for "k":
k = 8
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Solve for "x":
4x + 8 = 9k
4x = 72-8
4x = 64
x = 16
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A = 4x = 64 years old
B = 3x = 48 years old
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Cheers,
Stan H.
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