<PRE><B>Question 816600</B>
A shipment of 14 televisions contains 5 regular and 9 deluxe models. The manufacturer failed to mark the model designation on the cartons. If 3 cartons are selected at random, what is the probability that exactly 2 of them are the deluxe model? 
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# of ways to succeed: 9C2*5C1 = 36*5 = 180
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# of sets of 3:: 14C3 = (14*13*12)/(1*2*3) = 364
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P(x = 3) = 180/364 = 0.4945
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Cheers,
Stan H.
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