Question 816576
{{{x-7sqrt (x)+12=0}}}

{{{x+12=7sqrt (x)}}}......square both sides

{{{(x+12)^2=(7sqrt (x))^2}}}

{{{x^2+24x+144=49x }}}

{{{x^2+24x+144-49x =0}}}

{{{x^2-25x+144 =0}}}..................write {{{-25x}}} as {{{-16x-9x}}}

{{{x^2-16x-9x+144 =0}}}......group

{{{(x^2-16x)-(9x-144) =0}}}

{{{x(x-16)-9(x-16) =0}}}

{{{(x-16)(x-9) = 0}}}

solutions:

if {{{x-16 = 0}}} => {{{highlight(x=16)}}}

if {{{x-9 = 0}}} => {{{highlight(x=9)}}}


{{{ graph( 600, 600, -5, 20, -5, 10, x-7sqrt (x)+12) }}}