Question 69080
One approach is to write the equation first in the "slope-intercpt" form, then convert this to the "standard form".
First, find the slope of the line from the given information.  You have two points on the: (-3, 0) and (0, 6).  These are the given x- and y-intercepts, respectively.
From these two points you can find the slope using: {{{m = (y[2]-y[1])/(x[2]-x[1])}}}
{{{m = (6-0)/(0-(-3))}}}
{{{m = 6/3}}}
{{{m = 2}}}
So now you can write:
{{{y = 2x+b}}} but you have been given b, the y-intercept.  It's 6.
{{{y = 2x+6}}} This is the equationin the slope-intercept form. You now need to convert it to the standard form: {{{ax+by = c}}}
{{{y = 2x+6}}} Subtract y from both sides.
{{{0 = 2x-y+6}}} Subtract 6 from both sides.
{{{-6 = 2x-y}}} or {{{2x-y = -6}}}