Question 816563
if a triangle ABC exists then what is the length of AB if AC=10 BC=6 and the angle ACB= 120 degrees? How do I solve this
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The side opposite <ACB is AB
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Use the Law of Cosines to fing AB:
AB^2 = 10^2+6^2-2*10*6*cos(120)
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AB^2 = 166
AB =  12.88
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Cheers,
Stan H.