Question 69019
If you're looking to solve for x, treat is an equality. What you need to do is add 2 to all sides
{{{ 4<2x-2<10 }}}
{{{ 4+2<2x + cross(-2+2)<10+2 }}}
{{{ 6<2x<12 }}} Then divide each side by 2 to isolate x
{{{ 6/2<cross(2)x/cross(2)<12/2 }}}
{{{ 3<x<6 }}}
So x can be any number between 3 and 6, but remember x cannot equal 3 or 6.