Question 816281
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Hi,
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One base of a trapozoud is one smaller than twice the second base. b2 = 2b1 - 1
The height is three less than the smaller base. h = b1 - 3
A = {{{((b1 + b2)/2)h = ((b1 +(2b1-1))/2)(b1-3)= 44}}}
                        (3b1 - 1)(b1-3) = 88
                      3b1^2 -10b1 -85 = 0  Solve for b1