Question 69055
The 1st digit can't be 2 or 3
So, it has to be 5,6,or 9, or 3 choices
One digit is used up and there are 4 choices for the next digit
There are 3 choices for the next
There are 2 choices for the next
And 1 choice for the last
multiply all the choices together to get all the possible combination
{{{3*4*3*2*1 = 72}}} possible numbers greater than 41,000 using
each digit only once