Question 816099
x - 5y = 15
4x - 3y = 26


-4x + 20y = -60 {multiplied first equation by -4}
4x - 3y = 26 {second equation stays the same}
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17y = -34 {added the two equations}
y = -2   {divided each side by 17}


x - 5y = 15 {first equation}
x - 5(-2) = 15 {substituted -2, for y, into first equation}
x + 10 = 15 {multiplied}
x = 5 {subtracted 10 from each side}


x = 5 and y = -2
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