Question 816076
Simplify cscx- cosxcotx
I rewrote the problem using reciprocals and quotients to get {{{1/sinx- 1/secx*cosx/sinx}}}. Then I multiplied the reciprocals of cosx and cotx to get {{{1/sinx- 1cosx/secxsinx}}} I'm not sure what to do after that.
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cscx- cosxcotx
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= 1/sin - cos^2/sin
= (1 - cos^2)/sin
= sin^2/sin
= sin(x)