Question 815838
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Hi,
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V = {{{pi*r^2*h)}}}
18.0mm in diameter and 25.0mm long, with an axial hole 12.0mm in diameter
V(of steel) = {{{25pi}}}({{{(9mm)^2)}}} - {{{(6mm)^2)}}}) 
V(of steel) = {{{25mm*pi(45mm^2) = 1125*pi}}} mm^3