Question 815796
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Hi,
assuming You meant
{{{(3x^2+7x-6)/(27x^3 - 8) = (cross(3x -2) (x +3))/cross(3x-2)(9x^2 + 6x + 4)= (x+3)/( 9x^2 + 6x + 4)}}}
Note:  27x^3 - 8 = {{{3(x - 2/3)(9x^2 + 6x + 4)}}} 0r {{{(3x-2)(9x^2 +6x + 4)}}}
27x^3 - 8 factored using Synthetic Division and its root 2/3
2/3	27	0	0	-8
		18	12	8
	27	18	12	0