Question 815683
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Hi,
three times a number is added to the square of a number 'n' the result is 10. Find the number
  n^2 + 3n = 10
  n^2 + 3n - 10 = 0
 (n+5)(n-2) = 0
   (n+5) = 0 , n = -5
0r (n-2) = 0 , n = 2