Question 794832
{{{m^4+m^2+1=m^4-m^3+m^3+m^2+1}}}


{{{m^4-m^3+m^3+m^2+1=(m^4+m^3+m^2)+(1-m^3)}}}

now we can write...

{{{(m^4+m^3+m^2)+(1-m^3)=m^2*(m^2+m+1)+(1-m)(1+m+m^2)}}}

rearranging and grouping leads to

{{{(m^2+m+1)(m^2-m+1)}}}