Question 815177
{{{ highlight(2)}}}
{{{s-1 =13*((r-1)/11)>=1}}} is an integer,
and so is {{{(r-1)/11>=1}}} .
{{{s=13*((r-1))/11+1}}}


{{{r+s=13*((r-1)/11)+r+1}}}
{{{r+s=13*((r-1)/11)+(r-1)+2}}}


{{{r+s=(13/11+1)*(r-1)+2}}}
{{{r+s= (24/11)*(r-1)+2}}}
{{{r+s=24*((r-1)/11)+2 }}}
{{{r+s= 8*3*((r-1)/11)+2}}}
So {{{r+s}}} had a remainder of {{{highlight(2)}}} when divided by {{{8}}} , or by {{{3}}} , or by {{{24}}} .