Question 815326
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Hi,
 100 players in a football pool each week.  
p = 1/100 chances of winning = .01  Losing q = .99
P(winning more than one week)  = 1 - P(all losses) = 1 - {{{(16C0)(.01)^0(.99)^16}}}
                                                   = 1 - .8515
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p= .01 & q = .99
nCx = {{{n!/(x!(n-x)!)}}}