<PRE><B>Question 68955</B>
A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City.
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We know when they meet they will have traveled a total of 388 miles, and both will have traveled for 4 hours.
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Let s = speed of the train from G.C.
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Dist = time * speed
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Belleville train dist + G.C train dist = 388 mi
 4(47) + 4s = 388
 188 + 4s = 388
4s = 388 - 188
4s = 200
s = 200/4
s = 50 mph speed of train from G.C.
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Check 4(47) + 4(50) = 388
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