<PRE><B>Question 815316</B>
&lt;pre&gt;
x&lt;sup&gt;3&lt;/sup&gt; divided by (x+1)

Consider x&lt;sup&gt;3&lt;/sup&gt; as x&lt;sup&gt;3&lt;/sup&gt;+0x&lt;sup&gt;2&lt;/sup&gt;+0x+0

and either do it by long division:

   &lt;u&gt;     x²- x+1&lt;/u&gt;-{{{1/(x+1)}}}
x+1)x³+0x²+0x+0
    &lt;u&gt;x³+ x²&lt;/u&gt;
       -x²+0x
       &lt;u&gt;-x²- x&lt;/u&gt;
            x+0
            &lt;u&gt;x+1&lt;/u&gt;
             -1

Or by synthetic division:

-1|1  0  0  0 
  |&lt;u&gt;  -1  1 -1&lt;/u&gt;
   1 -1  1 -1

also yielding:  x²-x+1&lt;/u&gt;-{{{1/(x+1)}}} 

Edwin&lt;/pre&gt;                  </PRE>