Question 9108
-[3x-(2x+5)] = -4-[3(2x-4)-3x]
multiply both sides with '-1'
=> (-1)(-[3x-(2x+5)] )= (-1)(-{4+[3(2x-4)-3x]})
=> 3x-(2x+5) = 4+[3(2x-4)-3x]
=> 3x -2x -5 = 4 + 3(2x) - 3(4) - 3x
=> x - 5 = 4 + 6x - 12 - 3x
=> x - 6x + 3x = 5 + 4 - 12
=> - 2x = -3
multiply both sides with '-1'
=> 2x = 3
=> x = 3/2