Question 815168
y<=2x
2x+3y<=0
note that the first equation is solved for y, now we solve the second equation for y
3y <= -2x
y <= -2x/3
now we graph both inequalities
{{{ graph( 300, 200, -10, 10, -10, 10, y<2x, y<-2x/3) }}}
the shaded area is where the inequalities overlap
now let's look at the x values from each inequality
x >= y/2       from first equation
x <= -3y/2
we can combine the two inequalities
y/2 =< x <= -3y/2