Question 815058
Let n = the first
    n+2 the second
    n+4 the third
    n+6 the fourth

 (n  +  n+2  +  n+4  + n+6 )/4 =24
  4n + 12 = 24 
  Subtract 12 from each side
  4n = 12
   n = 3
So the numbers are 3 5 7 9