Question 814853
Let the integers be x, x+2, x+4.
2(x+x+2+x+4)=x(x+2)+7
2(3x+6)=x^2+2x+7
6x+12=...
x^2-4x-5=0
(x-5)(x+1)=0
x=5
x+2=7
x+4=9
.
Ed