Question 814851
{{{y=x+9}}}
{{{3y-2x=29}}}
since y is x+9 , you can replace the y in the 2nd equation with x+9.
{{{3(x+9)-2x=29}}}
{{{3x+27-2x=29}}}
{{{x+27=29}}}
{{{x=2}}}
now we can put 2 into the first equation.
{{{y=2+9}}}
{{{y=11}}}


The x value is 2 and the y value is 11.

The solution is (2,11).  This is where the lines cross.