Question 813861
is this the correct way of doing quadratic equation
x^2+x-6=0
(x+2)(x-3)
x+2=0 x-3=0
x=2   x=3
---------------
It's a correct way, when you can factor the polynomial.
-----
x^2+x-6=0
(x+2)(x-3)   *****  = 0  
x+2=0 x-3=0
x=2 **** x = -2
x=3