Question 68856
Here are the Steps using Substition method
1. In either equation, solve for one variable in terms of the other. We are going to solve for y in terms of x.
x+y=12
y = -x+12
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2. Substitute -x+12 for y in the other equation x+3/2y=3/2. Solve x.
{{{x+(3/2)y=3/2}}} , y = -x+12
{{{x +(3/2)(-x+12) = 3/2}}}
{{{x -(3/2)x + 18 = 3/2}}}
{{{(-1/2)x = -33/2}}}
x = 33
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3. Substitute the result from step 2 in either equation. Solve for the other variable y.
x+y=12 , x = 33
33 + y = 12
y = -21
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4. Check the solution in both original equations.
x+y=12, x = 33 y = -21
33 +(-21) = 12
33 - 21 = 12
12 = 12 ---------->> True
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{{{x+(3/2)y=3/2}}}, x = 33 y = -21
{{{33 + (3/2)(-21) = 3/2}}} 
{{{33 - (63/2) = 3/2}}}
{{{(66/2) - (63/2) = 3/2}}}
{{{3/2 = 3/2}}} ---------->> True