Question 813717
Write the equation in standard form for a hyperbola centered at (h,k) and identify the center and vertices.
x2 - 2x - y2 + 2y = 4 
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complete the square:
(x^2-2x+1)-(y^2-2y+1)=4+1-1
(x-1)^2-(y-1)^2=4
(x-1)^2/4-(y-1)^2/4=1
Given hyperbola has a horizontal transverse axis.
Its standard form of equation: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}
center: (1,1)
a^2=4
a=2
vertices: (1±a,1)=(1±2,1)=(-1,1) and (3,1)