Question 813796
Find an equation of the parabola that satisfies the given conditions.
Focus F(8, 4), directrix y = −2.
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Given data show parabola opens upwards.
Its basic form of equation:
{{{(x-h)^2=4p(y-k)}}}, (h,k)=(x,y) coordinates of the vertex, p=distance from vertex to focus and directrix on the axis of symmetry
For given parabola:
axis of symmetry: x=8
x-coordinate of vertex=8
y-coordinate of vertex=(4+(-2))/2=2/2=1 (midpoint between focus and directrix on the axis of symmetry.
Vertex:(8,1)
p=3 (distance from vertex to focus and directrix on the axis of symmetry.
4p=12
equation of given parabola:{{{(x-8)^2=12(y-1)}}}