Question 813735
The number of trout in a breeding pond is given by, Assume it's:
f(t) = {{{1400/(1+5e^(-0.09t))}}}
 where t is the number of months that have passed since the pond was stocked with trout.
:
How many trout were in the pond immediately after it was stocked?
Then t=0, e^0 = 1, therefore
f(t) = {{{1400/6}}}
f(t) ~ 233 trout
:
How many trout were in the pond 1 year after it was stocked?
f(t) = {{{1400/(1+5e^(-0.09*12))}}}
f(t) = {{{1400/(1+5(.34))}}}
f(t) = {{{1400/2.7}}}
f(t) = 519 trout
:
what will happen to the trout population as t increases without bound?
Eventually 5e becomes so close to 0, it will level off at around 1400 trout,
t = 100 months = 1399 trout